Upload all the previously solved exercises

Author: Ankononenko

For loop/06. Multiplication table.c

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+// Copyright 2022 finchren
+/* 
+Write a program in C to display the multiplication table of a given integer. Go to the editor
+Test Data :
+Input the number (Table to be calculated) : 15
+Expected Output :
+15 X 1 = 15
+...
+...
+15 X 10 = 150
+
++ 1. Take the input
++ 2. Display the multiplication table
++ 3. Work around invalid input
++ 4. Test
++ 5. Cpplint test
++ 6. Add and push
+*/
+
+#include <stdio.h>
+
+int main() {
+    int number, result;
+    char endline;
+    if (scanf("%d%c", &number, &endline) && ((endline == ' ') || (endline == '\n'))) {
+        for (int i = 1; i <= 10; i++) {
+            result = number * i;
+            printf("%d x %d = %d\n", number, i, result);
+        }
+    } else {
+        printf("n/a");
+    }
+    return 0;
+}

For loop/13. Pyramid with numbers - 00 - Old with mistakes.c

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+// Copyright 2022 finchren
+/* 
+Write a program in C to make such a pattern like a pyramid with numbers increased by 1. As input it takes the number of elements
+   1 
+  2 3 
+ 4 5 6 
+7 8 9 10 
+
++ 1. Take the input
++ 2. Display the numbers of the pyramid
++ 2.5 Display the spaces of the pyramid
++ 3. Work around invalid input
++ 4. Test
++ 5. Cpplint test
++ 6. Add and push
+*/
+
+#include <stdio.h>
+
+int number_of_rows(int number);
+void print_spaces(int number_of_rows);
+
+int main() {
+    int input_number, output_number = 1, rows;
+    char endline;
+    if (scanf("%d%c", &input_number, &endline) && ((endline == ' ') || (endline == '\n'))) {
+        rows = number_of_rows(input_number);
+        for (int i = 1; i <= input_number; i++) {
+            print_spaces(rows);
+            for (int j = 0; j < i; j++) {
+                printf("%d ", output_number);
+                input_number -= 1;
+                output_number++;
+            }
+            printf("\n");
+            rows -= 1;
+        }
+    } else {
+        printf("n/a");
+    }
+    return 0;
+}
+
+void print_spaces(int number_of_rows) {
+    for (int i = number_of_rows - 1; i > 0; i--) {
+        printf(" ");
+        }
+}
+
+int number_of_rows(int number) {
+    int result = 0;
+    for (int i = 1; i <= number; i++) {
+        for (int j = 0; j < i; j++) {
+                number -= j;
+            }
+        result++;
+    }
+    return result;
+}

For loop/13. Pyramid with numbers - 01 - Improved and working correctly.c

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+// Copyright 2022 finchren
+/* 
+Write a program in C to make such a pattern like a pyramid with numbers increased by 1. As input it takes the number of elements
+   1 
+  2 3 
+ 4 5 6 
+7 8 9 10 
+
++ 1. Take the input
++ 2. Display the numbers of the pyramid
++ 2.5 Display the spaces of the pyramid
++ 3. Work around invalid input
++ 4. Test
++ 5. Cpplint test
++ 6. Add and push
+*/
+
+#include <stdio.h>
+
+int number_of_rows(int number);
+void print_spaces(int number_of_rows);
+
+int main() {
+    int input_number, output_number = 1, rows;
+    char endline;
+    // Check if input is a number and there isn't any characters at the end except for space or a newline
+    if (scanf("%d%c", &input_number, &endline) && ((endline == ' ') || (endline == '\n'))) {
+        rows = number_of_rows(input_number) - 1;
+        // Check to see if we can build a symmetric pyramid out of the input number
+        if (rows > 0) {
+            for (int i = 1; i <= input_number; i++) {
+                print_spaces(rows);
+                for (int j = 0; j < i; j++) {
+                    printf("%d ", output_number);
+                    input_number -= 1;
+                    output_number++;
+                }
+                printf("\n");
+                rows -= 1;
+            }
+        } else {
+        printf("The symmetric pyramid cannot be build out of that number \n"
+        "Allowed numbers are 10, 15, 21, 28, 36, 45, 55, 66, 78 etc \n"
+        "Int the pyramid each row is begger than previos by one digit \n");
+        }
+    } else {
+        printf("n/a");
+    }
+    return 0;
+}
+
+void print_spaces(int number_of_rows) {
+    for (int i = number_of_rows; i > 0; i--) {
+        printf(" ");
+        }
+}
+
+// The function returns zero in case of invalid input
+// Invalid input - symmetric piramid cannot be build
+int number_of_rows(int number) {
+  int result = 0, counter = 0, temp = 0;
+    for (int i = 1; i <= number; i ++) {
+        temp += i;
+        counter++;
+        if (temp == number) {
+        result = counter;
+        }
+        if (temp > number) {
+          break;
+        }
+    }
+    return result;
+}

For loop/18. Find the sum of the series.c

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+// Copyright 2022 finchren
+/* 
+Write a program in C to find the sum of the series [ 1-X^2/2!+X^4/4!- .........]
+Test Data :
+Input the Value of x :2
+Input the number of terms : 5
+Expected Output :
+the sum = -0.415873
+Number of terms = 5
+value of x = 2.000000
++ 1. Take the input of x and number of terms
++ 2. Write factorial function
++ 2.1 Write pow function
+2.3 Write function for counting the sum
++ 2.5 Display the sum, number of term and value of x
++ 3. Work around invalid input
++ 4. Test
++ 5. Cpplint test
++ 6. Add and push
++ 7. Rework considering the Misha's comments
++ 8. Fix the error in the code
++ 9. Add and push fixed and reworked version
+*/
+
+#include <stdio.h>
+
+int input_value_of_x();
+int input_number_of_terms();
+int factorial(int number);
+int power(int base, int exponent);
+double count_sum(int x, int number_of_terms);
+void print_sum(double sum);
+void print_number_of_terms(int number_of_terms);
+void print_value_of_x(int x);
+void print_invalid_input();
+
+int main() {
+    int x = input_value_of_x();
+    if (x > 0) {
+        int number_of_terms = input_number_of_terms();
+        if (number_of_terms > 0) {
+            print_sum(count_sum(x, number_of_terms));
+            print_number_of_terms(number_of_terms);
+            print_value_of_x(x);
+        } else {
+        print_invalid_input();
+    }
+    } else {
+        print_invalid_input();
+    }
+    return 0;
+}
+
+void print_invalid_input() {
+    printf("n/a");
+}
+
+void print_value_of_x(int x) {
+    printf("Value of x = %f\n", (double)x);
+}
+
+void print_number_of_terms(int number_of_terms) {
+    printf("Number of terms = %d\n", number_of_terms);
+}
+
+void print_sum(double sum) {
+    printf("The sum = %f\n", sum);
+}
+
+double count_sum(int x, int number_of_terms) {
+    double sum = 1.0;
+    int multiplier = 2, sign = -1;
+    for (int i = 1; i < number_of_terms; ++i) {
+        sum += sign * power(x, multiplier) / (double)factorial(multiplier);
+        multiplier += 2;
+        sign *= (-1);
+    }
+    return sum;
+}
+
+int power(int base, int exponent) {
+    int result = base;
+    for (int i = 2; i <= exponent; ++i) {
+        result *= base;
+    }
+    return result;
+}
+
+int input_number_of_terms() {
+    int number_of_terms;
+    char endline;
+    printf("Input the number of terms:\n");
+    if (!scanf("%d%c", &number_of_terms, &endline) || (endline != '\n') || (number_of_terms <= 0)) {
+        number_of_terms = 0;
+    }
+    return number_of_terms;
+}
+
+int input_value_of_x() {
+    int x;
+    char endline;
+    printf("Input the value of x:\n");
+    if (!scanf("%d%c", &x, &endline) || endline != '\n') {
+        x = 0;
+    }
+    return x;
+}
+
+int factorial(int number) {
+    int result = 1;
+    for (int i = 1; i <= number; ++i) {
+        result *= i;
+    }
+    return result;
+}

For loop/19. Harmonic series and their sum.c

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+// Copyright 2022 finchren
+/* 
+Write a program in C to display the n terms of harmonic series and their sum.
+1 + 1/2 + 1/3 + 1/4 + 1/5 ... 1/n terms
+Test Data :
+Input the number of terms : 5
+Expected Output :
+1/1 + 1/2 + 1/3 + 1/4 + 1/5 +
+Sum of Series upto 5 terms : 2.283334
+
++ 1. Take the input of n
++ 2. Write a function to display expected output 
++ 3. Write a function to count sum
++ 4. Display the sum
++ 5. Invalid input
++ 6. Test
++ 7. Cpplint test
+8. Add and push
+*/
+
+#include <stdio.h>
+
+int input_n();
+void display_expected(int n);
+double count_sum(int n);
+void display_sum(double sum, int n);
+void invalid_input();
+
+int main() {
+    int n = input_n();
+    if (n > 0) {
+        display_expected(n);
+        double sum = count_sum(n);
+        display_sum(sum, n);
+    } else {
+        invalid_input();
+    }
+    return 0;
+}
+
+void invalid_input() {
+    printf("n/a");
+}
+
+void display_sum(double sum, int n) {
+    printf("Sum of Series upto %d terms: %lf", n, sum);
+}
+
+double count_sum(int n) {
+    double sum = 0;
+    for (int i = 1; i <= n; i++) {
+        sum += 1.0 / i;
+    }
+    return sum;
+}
+
+void display_expected(int n) {
+    for (int i = 1; i <= n; i++) {
+        printf("1/%d", i);
+        if (i != n) {
+            printf(" + ");
+        }
+    }
+    printf("\n");
+}
+
+int input_n() {
+    int n;
+    char endline;
+    printf("Input the number of terms:\n");
+    if ((!scanf("%d%c", &n, &endline)) || (endline != '\n')) {
+        n = 0;
+    }
+    return n;
+}