why is solutaion is not correct

[omprakashcs01]

n this kata you will create a function that takes a list of non-negative integers and strings and returns a new list with the strings filtered out.

Example
filter_list([1,2,'a','b']) == [1,2]
filter_list([1,'a','b',0,15]) == [1,0,15]
filter_list([1,2,'aasf','1','123',123]) == [1,2,123]

my solutaion :
function filter_list(l) {
return l.map(item => typeof item === 'number' ? item : null).filter(Boolean);
}

output:
For input [1,"a","b",0,15]: expected [ 1, 15 ] to deeply equal [ 1, +0, 15 ]

[hobovsky]

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