-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path100.isSameTree.py
63 lines (54 loc) · 1.23 KB
/
100.isSameTree.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
# Given the roots of two binary trees p and q, write a function to check if they are the same or not.
# Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.
#
#
#
# Example 1:
#
#
# Input: p = [1,2,3], q = [1,2,3]
# Output: true
# Example 2:
#
#
# Input: p = [1,2], q = [1,null,2]
# Output: false
# Example 3:
#
#
# Input: p = [1,2,1], q = [1,1,2]
# Output: false
#
#
# Constraints:
#
# The number of nodes in both trees is in the range [0, 100].
# -104 <= Node.val <= 104
# Seen this question in a real interview before?
# 1/4
# Yes
# No
# Accepted
# 2.1M
# Submissions
# 3.3M
# Acceptance Rate
# 61.8%
# Definition for a binary tree node.
from typing import Optional
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
# inorder traversal
if not p and not q:
return True
if not p or not q:
return False
# N L R
if p.val != q.val:
return False
return self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right)