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Copy path1963.minSwaps.py
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1963.minSwaps.py
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"""
You are given a 0-indexed string s of even length n. The string consists of exactly n / 2 opening brackets '[' and n / 2 closing brackets ']'.
A string is called balanced if and only if:
It is the empty string, or
It can be written as AB, where both A and B are balanced strings, or
It can be written as [C], where C is a balanced string.
You may swap the brackets at any two indices any number of times.
Return the minimum number of swaps to make s balanced.
Example 1:
Input: s = "][]["
Output: 1
Explanation: You can make the string balanced by swapping index 0 with index 3.
The resulting string is "[[]]".
Example 2:
Input: s = "]]][[["
Output: 2
Explanation: You can do the following to make the string balanced:
- Swap index 0 with index 4. s = "[]][][".
- Swap index 1 with index 5. s = "[[][]]".
The resulting string is "[[][]]".
Example 3:
Input: s = "[]"
Output: 0
Explanation: The string is already balanced.
Constraints:
n == s.length
2 <= n <= 106
n is even.
s[i] is either '[' or ']'.
The number of opening brackets '[' equals n / 2, and the number of closing brackets ']' equals n / 2.
"""
class Solution:
def minSwaps(self, s: str) -> int:
close, maxClose = 0, 0
for c in s:
if c == "[":
close -= 1
else:
close += 1 # find matchs
maxClose = max(maxClose, close)
return (maxClose + 1) // 2 # upscale
if __name__ == "__main__":
s = "] [] ["
print(Solution().minSwaps(s)) # 1