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使用gjson 替代gson.JSON #1175

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pengdaCN opened this issue Mar 21, 2025 · 1 comment

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enhance

pengdaCN commented Mar 21, 2025

gson 只是将返回值转为go的对象，不能提供获取原始值的能力，若我需要将返回值的某一个字段序列化，使用提供的Unmarshal 函数则会失败。
若使用gjson，则可以做到，而且gjson 会更加灵活

pengdaCN added the enhance label

github-actions bot commented Mar 21, 2025

Please add a valid Rod Version: v0.0.0 to your issue. Current version is v0.116.2

_{generated by check-issue}

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