Create 0832. Flipping an Image

Author: haibarawu

0832. Flipping an Image

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+/****************************************
+832. Flipping an Image
+
+Difficulty: Easy
+
+Given a binary matrix A, we want to flip the image horizontally, then invert it, and return the resulting image.
+
+To flip an image horizontally means that each row of the image is reversed.  
+For example, flipping [1, 1, 0] horizontally results in [0, 1, 1].
+
+To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0. 
+For example, inverting [0, 1, 1] results in [1, 0, 0].
+
+Example 1:
+Input: [[1,1,0],[1,0,1],[0,0,0]]
+Output: [[1,0,0],[0,1,0],[1,1,1]]
+Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
+Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
+
+Example 2:
+Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
+Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
+Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
+Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
+
+Notes:
+1 <= A.length = A[0].length <= 20
+0 <= A[i][j] <= 1
+
+****************************************/
+
+
+class Solution {
+    public int[][] flipAndInvertImage(int[][] A) {
+        return invertImage(flipImage(A));
+    }
+    
+    public int[][] invertImage(int[][] A) {
+        for(int i = 0; i < A.length; i++) {
+            for(int j = 0; j < A[i].length; j++) {
+                if (A[i][j] == 1) {
+                    A[i][j] = 0;
+                }
+                else {
+                    A[i][j] = 1;
+                }
+            }
+        }
+        return A;
+    }
+    
+    public int[][] flipImage(int[][] A){
+        for(int i = 0; i < A.length; i++) {
+            for(int j = 0; j < A[i].length / 2; j++) {
+                int temp = A[i][j];
+                A[i][j] = A[i][A.length - 1 - j];
+                A[i][A.length - 1 - j] = temp;
+            }
+        }
+        return A;
+    }
+}