Create minimum-length-of-anagram-concatenation.py

Author: kamyu104

Python/minimum-length-of-anagram-concatenation.py

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+# Time:  O(sqrt(n) * n + (26 * sum(n/i for i in range(1, n+1) if n%i == 0))) < O(sqrt(n) * n + 26 * sum(n/i for i in range(1, n+1)) = O(sqrt(n) * n + 26 * nlogn)
+# Space: O(26)
+
+# number theory, freq table
+class Solution(object):
+    def minAnagramLength(self, s):
+        """
+        :type s: str
+        :rtype: int
+        """
+        def factors(n):
+            for i in xrange(1, n+1):
+                if i*i > n:
+                    break
+                if n%i:
+                    continue
+                yield i
+                if n//i != i:
+                    yield n//i
+                    
+        def check(l):
+            def count(i):
+                cnt = [0]*26
+                for j in xrange(i, i+l):
+                    cnt[ord(s[j])-ord('a')] += 1
+                return cnt
+    
+            cnt = count(0)
+            return all(count(i) == cnt for i in xrange(l, len(s), l))
+
+        return min(l for l in factors(len(s)) if check(l))