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Create minimize-the-maximum-difference-of-pairs.cpp
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// Time: O(nlogn + nlogr), r = max(nums)-min(nums)
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// Space: O(1)
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// sort, binary search, greedy
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class Solution {
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public:
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int minimizeMax(vector<int>& nums, int p) {
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const auto& check = [&](int x) {
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int cnt = 0;
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for (int i = 0; i + 1 < size(nums) && cnt < p; ++i) {
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if (nums[i + 1] - nums[i] <= x) {
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++i;
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++cnt;
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}
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}
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return cnt == p;
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};
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sort(begin(nums), end(nums));
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int left = 0, right = nums.back() - nums.front();
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while (left <= right) {
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const int mid = left + (right - left) / 2;
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if (check(mid)) {
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right = mid - 1;
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} else {
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left = mid + 1;
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}
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}
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return left;
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}
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};

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