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Create maximum-subarray-sum-with-length-divisible-by-k.cpp
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// Time: O(n)
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// Space: O(k)
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// prefix sum, dp
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class Solution {
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public:
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long long maxSubarraySum(vector<int>& nums, int k) {
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static const int64_t INF = numeric_limits<int64_t>::max();
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vector<int64_t> dp(k, INF);
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dp.back() = 0;
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int64_t result = numeric_limits<int64_t>::min();
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for (int64_t i = 0, curr = 0; i < size(nums); ++i) {
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curr += nums[i];
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if (dp[i % k] != INF) {
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result = max(result, curr - dp[i % k]);
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}
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dp[i % k] = min(dp[i % k] , curr);
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}
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return result;
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}
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};

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