|
| 1 | +// Time: O(25 * l * (n + q)) |
| 2 | +// Space: O(25 * l * n) |
| 3 | + |
| 4 | +// hash |
| 5 | +class Solution { |
| 6 | +public: |
| 7 | + vector<string> twoEditWords(vector<string>& queries, vector<string>& dictionary) { |
| 8 | + static const uint64_t MOD = (1ull << 64) - 59; // largest 64-bit prime |
| 9 | + static const uint64_t BASE = 113; |
| 10 | + vector<uint64_t> POW = {1}; |
| 11 | + const auto& add = [](uint64_t a, uint64_t b) { |
| 12 | + if (MOD - a <= b) { |
| 13 | + b -= MOD; // relied on unsigned integer overflow in order to give the expected results |
| 14 | + } |
| 15 | + return a + b; |
| 16 | + }; |
| 17 | + const auto& sub = [&](uint64_t a, uint64_t b) { |
| 18 | + return add(a, MOD - b); |
| 19 | + }; |
| 20 | + const auto& mult = [&](uint64_t a, uint64_t b) { |
| 21 | + uint64_t result = 0; |
| 22 | + if (a < b) { |
| 23 | + swap(a, b); |
| 24 | + } |
| 25 | + while (b > 0) { |
| 26 | + if (b % 2 == 1) { |
| 27 | + result = add(result, a); |
| 28 | + } |
| 29 | + a = add(a, a); |
| 30 | + b /= 2; |
| 31 | + } |
| 32 | + return result; |
| 33 | + }; |
| 34 | + const auto& pow = [&](int i) { |
| 35 | + while (!(i < size(POW))) { |
| 36 | + POW.emplace_back(mult(POW.back(), BASE)); |
| 37 | + } |
| 38 | + return POW[i]; |
| 39 | + }; |
| 40 | + |
| 41 | + unordered_set<uint64_t> lookup; |
| 42 | + for (const auto& w : dictionary) { |
| 43 | + uint64_t h = 0; |
| 44 | + for (int i = 0; i < size(w); ++i) { |
| 45 | + h = add(h, mult(sub(w[i], 'a'), pow(i))); |
| 46 | + } |
| 47 | + for (int i = 0; i < size(w); ++i) { |
| 48 | + for (char x = 'a'; x <= 'z'; ++x) { |
| 49 | + if (x == w[i]) { |
| 50 | + continue; |
| 51 | + } |
| 52 | + lookup.emplace(add(h, mult(sub(x, w[i]), pow(i)))); |
| 53 | + } |
| 54 | + } |
| 55 | + } |
| 56 | + vector<string> result; |
| 57 | + for (const auto& w : queries) { |
| 58 | + uint64_t h = 0; |
| 59 | + for (int i = 0; i < size(w); ++i) { |
| 60 | + h = add(h, mult(sub(w[i], 'a'), pow(i))); |
| 61 | + } |
| 62 | + for (int i = 0; i < size(w); ++i) { |
| 63 | + char x = 'a'; |
| 64 | + for (; x <= 'z'; ++x) { |
| 65 | + if (x == w[i]) { |
| 66 | + continue; |
| 67 | + } |
| 68 | + if (lookup.count(add(h, mult(sub(x, w[i]), pow(i))))) { |
| 69 | + break; |
| 70 | + } |
| 71 | + } |
| 72 | + if (x <= 'z') { |
| 73 | + result.emplace_back(w); |
| 74 | + break; |
| 75 | + } |
| 76 | + } |
| 77 | + } |
| 78 | + return result; |
| 79 | + } |
| 80 | +}; |
| 81 | + |
| 82 | +// Time: O(q * n * l) |
| 83 | +// Space: O(1) |
| 84 | +// brute force |
| 85 | +class Solution2 { |
| 86 | +public: |
| 87 | + vector<string> twoEditWords(vector<string>& queries, vector<string>& dictionary) { |
| 88 | + const auto& check = [&](const auto& w1, const auto& w2) { |
| 89 | + int cnt = 0; |
| 90 | + for (int i = 0; i < size(w1); ++i) { |
| 91 | + cnt += static_cast<int>(w1[i] != w2[i]); |
| 92 | + } |
| 93 | + return cnt <= 2; |
| 94 | + }; |
| 95 | + |
| 96 | + vector<string> result; |
| 97 | + for (const auto& q : queries) { |
| 98 | + for (const auto& d : dictionary) { |
| 99 | + if (check(q, d)) { |
| 100 | + result.emplace_back(q); |
| 101 | + break; |
| 102 | + } |
| 103 | + } |
| 104 | + } |
| 105 | + return result; |
| 106 | + } |
| 107 | +}; |
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