Create SQL Exercises: Make a list of customers who appointed a salesman for their jobs who does not live in the same city where their customer lives, and gets a commission is above 12%

Author: mrmightyq

w3resource/SQL Exercises: Make a list of customers who appointed a salesman for their jobs who does not live in the same city where their customer lives, and gets a commission is above 12%

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+https://www.w3resource.com/sql-exercises/sql-joins-exercise-5.php
+
+SQL JOINS: Exercise-5 with Solution
+From the following tables write a SQL query to find those salespersons do not live in the same city where their customers live and received a commission from the company more than 12%. Return Customer Name, customer city, Salesman, salesman city, commission.
+
+Sample table: salesman
+salesman_id |    name    |   city   | commission 
+-------------+------------+----------+------------
+        5001 | James Hoog | New York |       0.15
+        5002 | Nail Knite | Paris    |       0.13
+        5005 | Pit Alex   | London   |       0.11
+        5006 | Mc Lyon    | Paris    |       0.14
+        5007 | Paul Adam  | Rome     |       0.13
+        5003 | Lauson Hen | San Jose |       0.12
+
+Sample table: customer
+ customer_id |   cust_name    |    city    | grade | salesman_id 
+-------------+----------------+------------+-------+-------------
+        3002 | Nick Rimando   | New York   |   100 |        5001
+        3007 | Brad Davis     | New York   |   200 |        5001
+        3005 | Graham Zusi    | California |   200 |        5002
+        3008 | Julian Green   | London     |   300 |        5002
+        3004 | Fabian Johnson | Paris      |   300 |        5006
+        3009 | Geoff Cameron  | Berlin     |   100 |        5003
+        3003 | Jozy Altidor   | Moscow     |   200 |        5007
+        3001 | Brad Guzan     | London     |       |        5005
+
+
+# Solution
+select a.cust_name as "Customer Name", a.city, b.name as"Salesman", b.commission 
+from customer as a 
+join salesman as b ON a.salesman_id=b.salesman_id
+where b.commission >.12 and a.city <> b.city
+;