Create # 44

Author: mrmightyq

w3resource/# 44

@@ -0,0 +1,41 @@
+# 44. From the following table, write a SQL query to find those departments where more than average number of employees works. Return department name.
+
+Employees
+ emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
+--------+----------+-----------+------------+------------+---------+------------+--------
+  68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
+  66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
+  67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
+  65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001
+  67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001
+  69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
+  63679 | SANDRINE | CLERK     |      69062 | 1990-12-18 |  900.00 |            |   2001
+  64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
+  65271 | WADE     | SALESMAN  |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
+  66564 | MADDEN   | SALESMAN  |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
+  68454 | TUCKER   | SALESMAN  |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
+  68736 | ADNRES   | CLERK     |      67858 | 1997-05-23 | 1200.00 |            |   2001
+  69000 | JULIUS   | CLERK     |      66928 | 1991-12-03 | 1050.00 |            |   3001
+  69324 | MARKER   | CLERK     |      67832 | 1992-01-23 | 1400.00 |            |   1001
+(14 rows)
+
+Department 
+ dep_id |  dep_name  | dep_location
+--------+------------+--------------
+   1001 | FINANCE    | SYDNEY
+   2001 | AUDIT      | MELBOURNE
+   3001 | MARKETING  | PERTH
+   4001 | PRODUCTION | BRISBANE
+(4 rows)
+
+SELECT d.dep_name
+FROM department d,
+     employees e
+WHERE e.dep_id = d.dep_id
+GROUP BY d.dep_name
+HAVING count(*) >
+  (SELECT AVG (mycount)
+   FROM
+     (SELECT COUNT(*) mycount
+      FROM employees
+      GROUP BY dep_id) a);