#Flatten Nested List Iterator ##Problem: Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1: Given the list [[1,1],2,[1,1]],
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1].
Example 2: Given the list [1,[4,[6]]],
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6].
##Idea:
Stack
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* class NestedInteger {
* public:
* // Return true if this NestedInteger holds a single integer, rather than a nested list.
* bool isInteger() const;
*
* // Return the single integer that this NestedInteger holds, if it holds a single integer
* // The result is undefined if this NestedInteger holds a nested list
* int getInteger() const;
*
* // Return the nested list that this NestedInteger holds, if it holds a nested list
* // The result is undefined if this NestedInteger holds a single integer
* const vector<NestedInteger> &getList() const;
* };
*/
class NestedIterator {
public:
NestedIterator(vector<NestedInteger> &nestedList) {
for(int i=(int)nestedList.size()-1;i>=0;i--)
{
nestedStack.push(nestedList[i]);
}
}
int next() {
NestedInteger top = nestedStack.top();
nestedStack.pop();
return top.getInteger();
}
bool hasNext() {
while(!nestedStack.empty())
{
NestedInteger top = nestedStack.top();
if(top.isInteger()) return true;
else
{
nestedStack.pop();
vector<NestedInteger>& topList=top.getList();
for(int i=(int)topList.size()-1;i>=0;i--)
{
nestedStack.push(topList[i]);
}
}
}
return false;
}
private:
stack<NestedInteger> nestedStack;
};
/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i(nestedList);
* while (i.hasNext()) cout << i.next();
*/