#Number of 1 Bits ##Problem: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.
##Idea:
bitmask
class Solution {
public:
int hammingWeight(uint32_t n) {
int count=0;
uint32_t mask=1;
while(mask)
{
if(n&mask) count++;
mask <<= 1;
}
return count;
}
};
##To Study: we can use n=n&(n-1) to clear the least significant 1
class Solution {
public:
int hammingWeight(uint32_t n) {
int count=0;
while(n)
{
n=n&(n-1);
count++;
}
return count;
}
};