510A - Fox And Snake.cpp

/*
Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.

A snake is a pattern on a n by m table. Denote c-th cell of r-th row as (r,?c). The tail of the snake is located at (1,?1), then it's body extends to (1,?m), then goes down 2 rows to (3,?m), then goes left to (3,?1) and so on.

Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').

Consider sample tests in order to understand the snake pattern.

Input
The only line contains two integers: n and m (3?=?n,?m?=?50).

n is an odd number.

Output
Output n lines. Each line should contain a string consisting of m characters. Do not output spaces.

Examples
inputCopy
3 3
outputCopy
###
..#
###
inputCopy
3 4
outputCopy
####
...#
####
inputCopy
5 3
outputCopy
###
..#
###
#..
###
inputCopy
9 9
outputCopy
#########
........#
#########
#........
#########
........#
#########
#........
#########

*/


#include<bits/stdc++.h>
using namespace std;


int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
	
	int m, n;
	cin >> m >> n;
	
	char a[m][n];
	
	for (int i  = 0; i < m; i++) {
		for (int j = 0; j < n; j++) {
			if(i % 2 == 0) a[i][j] = '#';
			else a[i][j] = '.';
		}
	}
	
	bool last = true;
	
	for (int i  = 1; i < m; i += 2) {
		if(last) a[i][n - 1] = '#';
		else a[i][0] = '#';
		last = !last;
	}
	
	
	for (int i  = 0; i < m; i++) {
		for (int j = 0; j < n; j++) {
			cout << a[i][j];
		}
		cout << endl;
	}
	    

}