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issue #3474 - adding ternary search data structure #3532

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1 change: 1 addition & 0 deletions data_structures/ternary search tree/dummy.txt
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1 change: 1 addition & 0 deletions data_structures/ternary search tree/python/dummy.txt
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66 changes: 66 additions & 0 deletions data_structures/ternary search tree/python/fenwick tree.py
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# Python implementation of Binary Indexed Tree

# Returns sum of arr[0..index]. This function assumes
# that the array is preprocessed and partial sums of
# array elements are stored in BITree[].
def getsum(BITTree,i):
s = 0 #initialize result

# index in BITree[] is 1 more than the index in arr[]
i = i+1

# Traverse ancestors of BITree[index]
while i > 0:

# Add current element of BITree to sum
s += BITTree[i]

# Move index to parent node in getSum View
i -= i & (-i)
return s

# Updates a node in Binary Index Tree (BITree) at given index
# in BITree. The given value 'val' is added to BITree[i] and
# all of its ancestors in tree.
def updatebit(BITTree , n , i ,v):

# index in BITree[] is 1 more than the index in arr[]
i += 1

# Traverse all ancestors and add 'val'
while i <= n:

# Add 'val' to current node of BI Tree
BITTree[i] += v

# Update index to that of parent in update View
i += i & (-i)


# Constructs and returns a Binary Indexed Tree for given
# array of size n.
def construct(arr, n):

# Create and initialize BITree[] as 0
BITTree = [0]*(n+1)

# Store the actual values in BITree[] using update()
for i in range(n):
updatebit(BITTree, n, i, arr[i])

# Uncomment below lines to see contents of BITree[]
#for i in range(1,n+1):
# print BITTree[i],
return BITTree


# Driver code to test above methods
freq = [2, 1, 1, 3, 2, 3, 4, 5, 6, 7, 8, 9]
BITTree = construct(freq,len(freq))
print("Sum of elements in arr[0..5] is " + str(getsum(BITTree,5)))
freq[3] += 6
updatebit(BITTree, len(freq), 3, 6)
print("Sum of elements in arr[0..5]"+
" after update is " + str(getsum(BITTree,5)))

# This code is contributed by Isaac Martin