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std.mutex: implement blocking mutexes on Linux #1463
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Original file line number | Diff line number | Diff line change |
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@@ -3,16 +3,31 @@ const builtin = @import("builtin"); | |
const AtomicOrder = builtin.AtomicOrder; | ||
const AtomicRmwOp = builtin.AtomicRmwOp; | ||
const assert = std.debug.assert; | ||
const linux = std.os.linux; | ||
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// Reading: Futexes Are Tricky by Ulrich Drepper https://www.akkadia.org/drepper/futex.pdf | ||
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// TODO robust mutexes https://www.kernel.org/doc/Documentation/robust-futexes.txt | ||
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/// TODO use syscalls instead of a spinlock | ||
pub const Mutex = struct { | ||
lock: u8, // TODO use a bool | ||
// TODO: Windows and OSX with futex equivilents | ||
// 0: unlocked | ||
// 1: locked, no waiters | ||
// 2: locked: one or more waiters | ||
lock: u32, // futexs are 32-bits on all architectures | ||
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pub const Held = struct { | ||
mutex: *Mutex, | ||
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pub fn release(self: Held) void { | ||
assert(@atomicRmw(u8, &self.mutex.lock, builtin.AtomicRmwOp.Xchg, 0, AtomicOrder.SeqCst) == 1); | ||
if (@atomicRmw(u32, &self.mutex.lock, AtomicRmwOp.Sub, 1, AtomicOrder.Release) != 1) { | ||
self.mutex.lock = 0; | ||
if (builtin.os == builtin.Os.linux) { | ||
_ = linux.futex_wake(@ptrToInt(&self.mutex.lock), linux.FUTEX_WAKE | linux.FUTEX_PRIVATE_FLAG, 1); | ||
} else { | ||
// spin-lock | ||
} | ||
} | ||
} | ||
}; | ||
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@@ -21,7 +36,28 @@ pub const Mutex = struct { | |
} | ||
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pub fn acquire(self: *Mutex) Held { | ||
while (@atomicRmw(u8, &self.lock, builtin.AtomicRmwOp.Xchg, 1, AtomicOrder.SeqCst) != 0) {} | ||
var c: u32 = undefined; | ||
// This need not be strong because of the loop that follows. | ||
// TODO implement mutex3 from https://www.akkadia.org/drepper/futex.pdf in x86 assembly. | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Is that really better? Can we have an issue to discuss it rather than this TODO comment? |
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if (@cmpxchgWeak(u32, &self.lock, 0, 1, AtomicOrder.Acquire, AtomicOrder.Monotonic)) |value1| { | ||
c = value1; | ||
while (true) { | ||
if (c == 2 or | ||
@cmpxchgWeak(u32, &self.lock, 1, 2, AtomicOrder.Acquire, AtomicOrder.Monotonic) == null) | ||
{ | ||
if (builtin.os == builtin.Os.linux) { | ||
_ = linux.futex_wait(@ptrToInt(&self.lock), linux.FUTEX_WAIT | linux.FUTEX_PRIVATE_FLAG, 2, null); | ||
} else { | ||
// spin-lock | ||
} | ||
} | ||
if (@cmpxchgWeak(u32, &self.lock, 0, 2, AtomicOrder.Acquire, AtomicOrder.Monotonic)) |value2| { | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Why does this jump straight to the "locked with waiters" state? shouldn't it just go back and try the original cmpxchg again? |
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c = value2; | ||
} else { | ||
break; | ||
} | ||
} | ||
} | ||
return Held{ .mutex = self }; | ||
} | ||
}; |
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You can't have a naked write racing with an atomic write (the cmpxchg on line 42).
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Why doesn't the
@atomicRmw
do an xchg and set the value to 0? You can still check if the previous value was 1.